
When is $A^TA$ invertible? - Mathematics Stack Exchange
Feb 26, 2023 · When is $A^TA$ invertible? Ask Question Asked 2 years, 9 months ago Modified 2 years, 9 months ago
How can we show that $ (I-A)$ is invertible? - Mathematics Stack …
How can we show that $ (I-A)$ is invertible? Ask Question Asked 13 years, 9 months ago Modified 7 years ago
linear algebra - Prove that $A+I$ is invertible if $A$ is nilpotent ...
Prove that $A+I$ is invertible if $A$ is nilpotent [duplicate] Ask Question Asked 13 years, 7 months ago Modified 5 years, 11 months ago
Is every injective function invertible? - Mathematics Stack Exchange
Sep 25, 2015 · A function is invertible if and only if it is bijective (i.e. both injective and surjective). Injectivity is a necessary condition for invertibility but not sufficient.
When does the inverse of a covariance matrix exist?
Oct 14, 2015 · We also know that every symmetric positive definite matrix is invertible (see Positive definite). It seems that the inverse of a covariance matrix sometimes does not exist. …
Why does a determinant of $0$ mean the matrix isn't invertible?
3 I always got taught that if the determinant of a matrix is $0$ then the matrix isn't invertible, but why is that? My flawed attempt at understanding things: This approaches the subject from a …
Can a matrix be invertible but not diagonalizable? [duplicate]
Mar 29, 2017 · Then the associated matrix is invertible (the inverse being the rotation of $-\theta$) but is not diagonalisable, since no non-zero vector is mapped into a multiple of itself by a …
matrices - Why is the nullity of an invertible matrix 0?
Apr 30, 2018 · By the invertible matrix theorem, one of the equivalent conditions to a matrix being invertible is that its kernel is trivial, i.e. its nullity is zero. I will prove one direction of this …
Prove that the product of two invertible matrices also invertible
Apr 28, 2016 · I know that the product matrix of two invertible matrices must be invertible as well, but I am not sure how to prove that. I am trying to show it through the product of determinants …
linear algebra - Proof that columns of an invertible matrix are ...
1 we want to proove that A is invertible if the column vectors of A are linearly independent. we know that if A is invertible than rref of A is an identity matrix so the row vectors of A are linearly …